Writing Combinations
About 909 wordsAbout 11 min
2025-08-18
The given regular expression is (ab∪ba)(aa∪bb)∗ab.
Let's break down the structure of any word, let's call it w, generated by this expression:
- Prefix: The word must start with either
aborba. This part has a fixed length of 2. - Middle: This part is described by (aa∪bb)∗. The Kleene star (∗) means "zero or more repetitions". This means the middle can be the empty string (ϵ), or
aa, orbb, oraaaa, oraabb, etc. Crucially, any string in this middle part will have an even length (0, 2, 4, 6, ...). - Suffix: The word must end with
ab. This part has a fixed length of 2.
The total length of any word is 2 (prefix) +length of middle part+2 (suffix). So, the total length will be 4+(an even number). This means the possible lengths of the words are 4, 6, 8, 10, and so on.
We are asked for all words of length less than or equal to 8. So we only need to consider words of length 4, 6, and 8.
1. Words of Length 4: For the total length to be 4, the middle part must have a length of 0. This means we use zero repetitions from (aa∪bb)∗, which gives us the empty string, ϵ.
- Prefix
ab+ Middleε+ Suffixab→ abab - Prefix
ba+ Middleε+ Suffixab→ baab
2. Words of Length 6: For the total length to be 6, the middle part must have a length of 2. This means we use one repetition from (aa∪bb)∗. The middle part can be aa or bb.
- Prefix
ab+ Middleaa+ Suffixab→ abaaab - Prefix
ab+ Middlebb+ Suffixab→ abbbab - Prefix
ba+ Middleaa+ Suffixab→ baaaab - Prefix
ba+ Middlebb+ Suffixab→ babbab
3. Words of Length 8: For the total length to be 8, the middle part must have a length of 4. This means we use two repetitions from (aa∪bb)∗. The possible middle parts are:
aafollowed byaa→aaaaaafollowed bybb→aabbbbfollowed byaa→bbaabbfollowed bybb→bbbb
Now we combine these with the prefixes and suffix:
- Prefix
ab+ Middleaaaa+ Suffixab→ abaaaaab - Prefix
ab+ Middleaabb+ Suffixab→ abaabbab - Prefix
ab+ Middlebbaa+ Suffixab→ abbbaaab - Prefix
ab+ Middlebbbb+ Suffixab→ abbbbbab - Prefix
ba+ Middleaaaa+ Suffixab→ baaaaaab - Prefix
ba+ Middleaabb+ Suffixab→ baaab bab - Prefix
ba+ Middlebbaa+ Suffixab→ babbaaab - Prefix
ba+ Middlebbbb+ Suffixab→ babbbbab
Summary of All Words
The words of length less than or equal to 8 are:
- Length 4:
abab,baab - Length 6:
abaaab,abbbab,baaaab,babbab - Length 8:
abaaaaab,abaabbab,abbbaaab,abbbbbab,baaaaaab,baaab bab,babbaaab,babbbbab
Skills to Solve Similar Questions
Here is a systematic approach you can use for any similar problem:
1. Deconstruct the Regular Expression First, break the expression down into its main components. Understand what each symbol means:
- Concatenation: Characters next to each other mean "followed by". For example,
abmeansafollowed byb. - Union (
∪or|): This means "OR". For example,(a ∪ b)means you can chooseaorb. - Kleene Star (
*): This means "zero or more repetitions" of the preceding element. For example,a*can be ϵ (the empty string),a,aa,aaa, etc. - Positive Closure (
+): This means "one or more repetitions". It's like the Kleene star, but you can't have zero repetitions.a+can bea,aa,aaa, etc.
2. Analyze the Word Structure and Length
- Identify the fixed parts of the expression (those without a
*or+). In your problem,(ab ∪ ba)andabare fixed blocks. - Identify the variable parts (those with a
*or+). In your problem,(aa ∪ bb)*is the variable part. - Calculate the minimum possible length of a word. This occurs when the Kleene star (
*) part is repeated zero times (i.e., it's the empty string). - Determine how the length changes. Notice that the variable part in your expression,
(aa ∪ bb), always adds 2 to the length. This allows you to find a pattern for possible word lengths (e.g., 4, 6, 8, ...).
3. Apply the Constraints Systematically
- The problem will almost always give you a constraint, like "length less than or equal to 8".
- Use the length analysis from the previous step to figure out which cases you need to examine. For your problem, you realized you only need to check lengths 4, 6, and 8.
- Work through each case one by one. For example:
- "To get length 4, what must the variable part be?"
- "To get length 6, what must the variable part be?"
- And so on.
4. Generate All Combinations Methodically
- For each case (e.g., for each length), list out all possible choices for each part of the expression.
- Combine them piece by piece. If there's a prefix
(a ∪ b)and a suffix(c ∪ d), make sure you test all four combinations:ac,ad,bc,bd. - Being organized is key to not missing any words or writing down duplicates. Listing them in alphabetical or structural order helps.
Changelog
0f9da-feat: add notes for writing diff combinationson
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Copyright Ownership:WARREN Y.F. LONG
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